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Grid Compensation & Power Quality · Part 2 of 4

STATCOM: sizing the hardware

Redirect reactive power, restore voltage and size the inverter coupling inductance.

01

Live experiment

Educational example · phase RMS quantities · balanced three-phase system

GridSTATCOMLoadP →Q →P = 80 kWQ load = 72.71 kvarQ comp = 40.71 kvarQ grid = 32 kvar
Power balance · kW / kvar
00.5 msp.u.
50 HzPWM
Switching detail · 0.5 ms window
Compensator RMS current
59.01 A
Minimum DC voltage
722.82 V
Coupling inductance
0.87 mH
Grid reactive power
32 kvar

02

Model & equations

The inverter supplies the required reactive power locally. The grid retains the active power and any allowed residual reactive power. Ripple is specified peak-to-peak relative to the fundamental peak current.

Qcomp=max⁡(0,Qload−Ptan⁡φ′),Icomp=Qcomp3VgQ_{comp}=\max(0,Q_{load}-P\tan\varphi'),\quad I_{comp}=\frac{Q_{comp}}{3V_g}
Emin=22Vgma,max,L=E6.9fcΔIpp,ΔIpp=r2IcompE_{min}=\frac{2\sqrt2 V_g}{m_{a,max}},\quad L=\frac{E}{6.9 f_c\Delta I_{pp}},\quad\Delta I_{pp}=r\sqrt2 I_{comp}
E=750 V>Emin=722.82 VE=750\,\mathrm{V}>E_{min}=722.82\,\mathrm{V}

03

Example parameters

Vg
230 V RMS
f
50 Hz
E
750 V
Rcc
0.05 Ω
Xcc
0.1 Ω
R
0.05 Ω
Rf
0.6 Ω
P
80 kW
cos φ
0.74
fc
10 kHz
L
0.87 mH
Δt
1 ms